Python获取HTTP请求的状态码(200,404等),不访问整个页面源码,那样太浪费资源:
输入:segmentfault.com 输出:200
输入:segmentfault.com/nonexistant 输出:404
参考文章:Python实用脚本清单
http不只有get
方法(请求头部
+正文
),还有head
方法,只请求头部
。
import httplib
def get_status_code(host, path="/"):
""" This function retreives the status code of a website by requesting
HEAD data from the host. This means that it only requests the headers.
If the host cannot be reached or something else goes wrong, it returns
None instead.
"""
try:
conn = httplib.HTTPConnection(host)
conn.request("HEAD", path)
return conn.getresponse().status
except StandardError:
return None
print get_status_code("segmentfault.com") # prints 200
print get_status_code("segmentfault.com", "/nonexistant") # prints 404